Question

The boiling point of ethanol is 78°C. What would it be in kelvin?

Answer 1

`351K`

Explanation:

1. Derive formula from the following data:
   Boiling Pt of water
   `K=373`
   `C=100^o`
   Freezing Pt of Water
   `K=273`
   `C=0^o`
2. Write the ratio of the 2 temperature scales with the zero points and the unit sizes
   `(K-273)/(373-273)=(C-0)/(100-0)`
3. Simplify
   `(K-273)/cancel100=C/cancel100`
4. 100 are cancelled since these 2 scales have same unit sizes so that the formula is;
   `K-273=C`
5. Isolate `K` by adding 273 both sides of the equation
   `K=C+273`
6. Plug in the given data `C=78^o` to the derived formula
7. The answer is `351K`