# The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost$3.68. How do you find the cost of each?

Jan 18, 2017

I found:
Oranges: $0.26 Apples: $0.32

#### Explanation:

Let us call the cost of oranges $O r$ and apples $A p$. We can write:

$12 O r + 7 A p = 5.36$
and
$8 O r + 5 A p = 3.68$

we can extract from the first:

$O r = \frac{5.36 - 7 A p}{12}$

we substitute this into the second equation for $O r$:

${\cancel{8}}^{2} \cdot \frac{5.36 - 7 A p}{\cancel{12}} ^ 3 + 5 A p = 3.68$

solve for $A p$:

$10.72 - 14 A p + 15 A p = 11.04$

$A p = 0.32$

use this value bach into the first equation:

$O r = \frac{5.36 - 7 A p}{12} = \frac{5.36 - 7 \cdot 0.32}{12} = 0.26$