# The density of a 20% by mass solution of sulphuric acid is 1.14g/mL. Calculate the mass of hydrogen sulphate in one litre of the solution. ?

Jul 15, 2018

Well, what is the mass of $1 \cdot L$ of this solution....?

#### Explanation:

Well, we are given the density....and so...

$\text{mass of solution} = 1 \cdot L \times 1000 \cdot m L \cdot {L}^{-} 1 \times 1.14 \cdot g \cdot m {L}^{-} 1$

$\equiv 1140 \cdot g$...OF WHICH 20% by mass is ${H}_{2} S {O}_{4}$...

And so [H_2SO_4]=((1140*gxx20%)/(98.08*g*mol^-1))/(1*L)=2.33*mol*L^-1...

Sulfuric acid is of course diprotic in aqueous solution...

${H}_{2} S {O}_{4} \left(a q\right) + {H}_{2} O \left(l\right) \rightarrow H S {O}_{4}^{-} + {H}_{3} {O}^{+}$

$H S {O}_{4}^{-} + {H}_{2} O \left(l\right) \rightarrow S {O}_{4}^{2 -} + {H}_{3} {O}^{+}$

The first reaction is to all intents and purposes quantitative. The second reaction lies to the right as we face the page. We have no data to address the extent of the equilibrium....