# The equation #a^3+b^3+c^3=2008# has a solution in which #a,b,and c# are distinct even positive integers. find #a+b+c#?

##### 1 Answer

Jun 18, 2018

#### Answer:

The answer is

#### Explanation:

The equation is

Since

Therefore,

Therefore,

Therefore,

Let

Then

Therefore,

Let

Finally