The equation of a parabola is (y−1)^2=16(x+3) . What is the equation of the directrix of the parabola? Enter your answer in the box.

1 Answer
May 24, 2018

Equation of directrix is #x = -7#

Explanation:

The standard equation of parabola opening right is

#(y-k)^2= 4 p(x-h)# , where #(h,k) being vertex and directrix

is #x= h-p #. In equation # (y-1)^2= 16 (x +3) ; h= -3 , p= 4#

Therefore directrix is #x=-3-4 or x = -7#

graph{(y-1)^2=16(x+3) [-45, 45, -22.5, 22.5]} [Ans]