# The equation of line QR is y = - 1 /2 x + 1. How do you write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6)?

##### 1 Answer

See a solution process below:

#### Explanation:

First, we need to find the slope of the for the two points in the problem. The line QR is in slope-intercept form. The slope-intercept form of a linear equation is:

Where

Therefore the slope of QR is:

Next, let's call the slope for the line perpendicular to this

The rule of perpendicular slopes is:

Substituting the slope we calculated gives:

We can now use the slope-intercept formula. Again, the slope-intercept form of a linear equation is:

Where

Substituting the slope we calculated gives:

We can now substitute the values from the point in the problem for

Substituting this into the formula with the slope gives: