The formula for finding the discharge of a river is (velocity of water) * (cross section of channel). What would be the discharge of a stream that moves at #1.5# #m##/##s# through an area of #520# #m##/##s^2#?

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Answer 1 · 2018-06-08T06:05:24

The discharge is #=780m^3s^-1#

I think that the units of area is #=m^2#

The velocity of water is #u=1.5ms^-1#

The cross section of the channel is #a=520m^2#

The discharge (flow) of the river is

#q=au=520*1.5=780m^3s^-1#