The gap between electrodes in a spark plug is 0.060 cm. To produce an electric spark in a gasoline-air mixture, there must be an electric field of #3.0 * 10^6# V/m. What minimum potential difference must be supplied by the ignition circuit to start a car?

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Answer 1 · 2017-03-05T21:31:45

The min potential difference is #1800 V#

Are you familiar with this idea:

#E = -(Delta V)/(Delta x)#

If so:

# Delta V = - E * Delta x#

# = - 3 times 10^6 cdot 0.06/100#

# = -1800 V#

The min potential difference is #1800 V#