# The gas in a closed container has a pressure of #3.00 * 10^2# #kPa# at #30°C# #(303 K)#. What will the pressure be if the temperature is lowered to #-172°C# #(146 K)#?

##### 1 Answer

Feb 22, 2016

The final pressure will be 145 kPa.

#### Explanation:

This is an example of Gay-Lussac's law, which states that the pressure of a given gas is directly proportional to its Kelvin temperature, when held at a constant volume. The equation that represents this law is

**Given/Known**

**Unknown**

**Solution**

Rearrange the equation to isolate

**Kelvin temperature changed to 146 K, which is

Excellent Resource for the gas laws: http://chemistry.bd.psu.edu/jircitano/gases.html