The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #85 ^o K#. If the temperature of the gas changes to #17 ^oK# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-05-19T16:47:48

#2.4 Pa#

We can solve this problem using the pressure-temperature relationship for gases, illustrated by Gay-Lussac's law:

#(P_1)/(T_1) = (P_2)/(T_2)#

We can rearrange this equation to solve for #P_2#, and plug in known variables to find it:

#P_2 = ((P_1)(T_2))/(T_1)#

#P_2 = ((12Pa)(17K))/(85K) = 2.4Pa#