# The gas inside of a container exerts 12 Pa of pressure and is at a temperature of 85 ^o K. If the temperature of the gas changes to 17 ^oK with no change in the container's volume, what is the new pressure of the gas?

May 19, 2017

$2.4 P a$

#### Explanation:

We can solve this problem using the pressure-temperature relationship for gases, illustrated by Gay-Lussac's law:

$\frac{{P}_{1}}{{T}_{1}} = \frac{{P}_{2}}{{T}_{2}}$

We can rearrange this equation to solve for ${P}_{2}$, and plug in known variables to find it:

${P}_{2} = \frac{\left({P}_{1}\right) \left({T}_{2}\right)}{{T}_{1}}$

${P}_{2} = \frac{\left(12 P a\right) \left(17 K\right)}{85 K} = 2.4 P a$