The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #650 ^o K#. If the temperature of the gas changes to #240 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-03-09T11:25:03

#approx 11.8 "Pa" #

Use the ideal gas law:

#pV =n RT#

Leaving out the constants/ things that don't change, this then boils down to:

#p propto T# or #p/T = const#, aka Gay-Lussac's Law

Remembering that #T# is the absolute temperature in Kelvin, you then have:

#p_2 = T_2 p_1/T_1 = (240 + 273) cdot 15/650 approx 11.8 "Pa" #