# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 180 ^o K. If the pressure in the container changes to 32 Pa with no change in the container's volume, what is the new temperature of the gas?

Apr 17, 2017

The new temperature is $= 384 K$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

Initial pressure is ${P}_{1} = 15 P a$

Initial temperature is ${T}_{1} = 180 K$

Final pressure is ${P}_{2} = 32 P a$

Final temperature is

${T}_{2} = {P}_{2} / {P}_{1} \cdot {T}_{1}$

$= \frac{32}{15} \cdot 180 = 384 K$