Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `275 ^o K`. If the pressure in the container changes to `32 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

`T_2=586.67 ^o K`

Explanation:

`P_i=15Pa`
`T_i=275^o K`

`P_f=32Pa`
`T_f=?`

`P_İ/T_İ=P_f/T_f`

`15/275=32/T_2`

`T_2=(275*32)/15`

`T_2=586.67 ^o K`