# The gas inside of a container exerts 16 Pa of pressure and is at a temperature of 430 ^o K. If the temperature of the gas changes to 150 ^oC with no change in the container's volume, what is the new pressure of the gas?

Nov 22, 2017

$\text{16.26 Pa}$

#### Explanation:

Gay-Lussac's law: For a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

Mathematically,

P ∝ T

${P}_{1} / {P}_{2} = {T}_{1} / {T}_{2}$

P_2 = P_1 × T_2/T_1

${P}_{2} = \text{16 Pa" × "430 K"/"(150 + 273)K" = "16.26 Pa}$