The gas inside of a container exerts #24 Pa# of pressure and is at a temperature of #85 ^o K#. If the temperature of the gas changes to #125 ^oK# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-11-17T06:46:34

The new pressure is #=35.3Pa#

Here, we use Gay Lussac's law

#P_1/T_1=P_2/T_2#

#P_1=24Pa#

#T_1=85K#

#T_2=125K#

#P_2=P_1/T_1*T_2=24*125/85=35.3Pa#