# The gas inside of a container exerts 24 Pa of pressure and is at a temperature of 85 ^o K. If the temperature of the gas changes to 125 ^oK with no change in the container's volume, what is the new pressure of the gas?

Nov 17, 2016

The new pressure is $= 35.3 P a$

#### Explanation:

Here, we use Gay Lussac's law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

${P}_{1} = 24 P a$

${T}_{1} = 85 K$

${T}_{2} = 125 K$

${P}_{2} = {P}_{1} / {T}_{1} \cdot {T}_{2} = 24 \cdot \frac{125}{85} = 35.3 P a$