The gas inside of a container exerts #24 Pa# of pressure and is at a temperature of #210 ^o K#. If the pressure in the container changes to #60 Pa# with no change in the container's volume, what is the new temperature of the gas?
The new temperature is
The answer can be determined by using Gay-Lussac's law:
The number 1 represents the initial conditions and the number 2 represents the final conditions.
Identify your known and unknown variables:
Rearrange the equation to solve
Plug in your given values to obtain the final temperature:
I should also mention that when you are dealing with the Kelvin scale, don't write the degrees symbol. Just write the letter K.