# The gas inside of a container exerts 25 Pa of pressure and is at a temperature of 430 ^o K. If the temperature of the gas changes to 150 ^oC with no change in the container's volume, what is the new pressure of the gas?

Apr 24, 2016

$24.6 P a$

#### Explanation:

From Boyle's Law and associated gas laws we get that

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

Since volume remains constant, we may cancel the $V$ terms, and write the others in SI units and solve for the required quantity to get ;

$\frac{25 P a}{430 K} = {P}_{2} / \left(423 K\right)$

$\therefore {P}_{2} = 24.6 P a$