The gas inside of a container exerts #25 Pa# of pressure and is at a temperature of #430 ^o K#. If the temperature of the gas changes to #150 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-04-24T18:29:21

#24.6Pa#

From Boyle's Law and associated gas laws we get that

#(P_1V_1)/T_1=(P_2V_2)/T_2#

Since volume remains constant, we may cancel the #V# terms, and write the others in SI units and solve for the required quantity to get ;

#(25Pa)/(430K)=P_2/(423K)#

#therefore P_2=24.6Pa#