# The gas inside of a container exerts 3 Pa of pressure and is at a temperature of 480 ^o K. If the temperature of the gas changes to 220 ^oC with no change in the container's volume, what is the new pressure of the gas?

Jan 14, 2017

1.9 Pa

#### Explanation:

We know ${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$ when volume remains same.

here P_1 = 3 Pa, T_1 = 480 + 273 = 753 k, P_2 = ?

and ${T}_{2} = 220 + 273 = 493 k$

Now, $\frac{3}{753} = {P}_{2} / 493$

${P}_{2} = \frac{3 \cdot 493}{753}$

${P}_{2} = 1.9 P a$