The gas inside of a container exerts #42 Pa# of pressure and is at a temperature of #420 ^o K#. If the pressure in the container changes to #72 Pa# with no change in the container's volume, what is the new temperature of the gas?

1 Answer
Apr 25, 2018

Answer:

#"final temperature is "720 ^o K#

Explanation:

#"As the volume of the container does not change, the increase of"#
#"the gas pressure causes the temperature to increase."#

#"We need to use the Gay-Lussac law to find the temperature."#

#P_i=42 Pa("initial pressure of the gas")#
#P_f=72 Pa("final pressure of the gas")#
#T_1=420 ^o K("initial temperature of the gas")#
#T_f=?("final temperature of the gas")#

#P_i/T_i=P_f/T_f#

#cancel(42)/cancel(420)=72/T_f#

#"let's divide both numerator and denominator by 42 "#

#1/10=72/T_f#

#1*T_f=72*10#

#T_f=720 ^oK#