The gas inside of a container exerts #5 Pa# of pressure and is at a temperature of #190 ^o K#. If the pressure in the container changes to #32 Pa# with no change in the container's volume, what is the new temperature of the gas?

1 Answer
Mar 6, 2016

Answer:

New temperature of the gas is #1216^oK#

Explanation:

Pressure #P#, volume #V# and temperature #T# (in Kelvin) have the relation #PV/T=k# where #k# is a constant.

As there is no change in the container's volume, it means that #P_1/T_1=P_2/T_2#

In the given case, gas inside of a container exerts #5Pa# of pressure and is at a temperature of #190^oK#. When pressure of the gas changes to #32Pa#, if the temperature becomes #T_2#, we should have

#5/190=32/T_2# or #T_2=((190xx32)/5)#

i.e. #P_2=6080/5=1216^oK#.