The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #650 ^o K#. If the temperature of the gas changes to #210 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-10-22T06:06:28

9.46Pa

By ideal gas law volume remaining constant Pressure is proportional to Temperature in Kelvin scale

Given

#P1-> "Initial pressure of the gas"=9Pa#

#T_1-> "Initial Temperature of the gas"=650K#

#P_2-> "Final pressure of the gas"=?#

#T_2-> "Final Temperature of the gas"=210^@C=683K#

By the ideal gas law

#P_1/T_1=P_2/T_2#

#=>P_2=(P_1T_2)/T_1=(9xx683)/650~~9.46Pa#