# The heat of fusion for water is 80. cal/g. How many calories of heat are needed to melt a 35 g ice cube that has a temperature of 0 C?

Jul 11, 2016

You need 2.8 × 10^3 color(white)(l)"cal" to melt the ice cube.

#### Explanation:

The formula for the heat required to melt a solid is

color(blue)(|bar(ul(color(white)(a/a) q= mΔ_"fus"H^°color(white)(a/a)|)))" "

where

$q = \text{the amount of heat}$
$m = \text{the mass of the solid}$
Δ_"fus"H^° = "the enthalpy of fusion"

$m = \text{35 g}$
Δ_"fus"H^° = "80. cal·g"^"-1""

q = 35 color(red)(cancel(color(black)("g"))) × "80. cal"·color(red)(cancel(color(black)("g"^"-1"))) = 2bar8 00color(white)(l) "cal" = 2.8 × 10^3 color(white)(l)"cal"