# The hypotenuse is 6, and one of the leg is 4. How do you find the missing leg length?

Mar 10, 2016

$2 \sqrt{5}$

#### Explanation:

Consider

Use pythagoras theorem

${a}^{2} + {b}^{2} = {c}^{2}$

Where

a and b are the right containing sides
c is the Hypotenuse

$\therefore {4}^{2} + {b}^{2} = {6}^{2}$

$\rightarrow 16 + {b}^{2} = 36$

$\rightarrow {b}^{2} = 36 - 6$

$\rightarrow {b}^{2} = 20$

$\Rightarrow b = \sqrt{20} = \sqrt{4 \cdot 5} = 2 \sqrt{5}$