The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and weighed 93.3 kg. What was the volume of this nugget in #cm^3# and liters? Chemistry Measurement Density 1 Answer anor277 Mar 21, 2016 Answer: We need the density of gold, #rho_(Au)# #=# #19.32# #g*cm^-3# Explanation: So, we divide mass by density to get the volume: #(93.3xx10^3*cancelg)/(19.32*cancelg*cm^-3)# #=# #4829.1# #cm^3#; approx a 5 litre volume. Related questions How can density be used to identify substances? How can you find mass from density? How are density mass and volume related? How do you calculate mass using density and volume? How do you convert mass to density? How do you determine the density of a gas? What is the density of water? What is linear mass density? Why does density change with temperature? How does density affect ocean currents? See all questions in Density Impact of this question 1391 views around the world You can reuse this answer Creative Commons License