The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and weighed 93.3 kg. What was the volume of this nugget in #cm^3# and liters?

1 Answer
Mar 21, 2016

Answer:

We need the density of gold, #rho_(Au)# #=# #19.32# #g*cm^-3#

Explanation:

So, we divide mass by density to get the volume:

#(93.3xx10^3*cancelg)/(19.32*cancelg*cm^-3)# #=# #4829.1# #cm^3#; approx a 5 litre volume.