Question

The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and weighed 93.3 kg. What was the volume of this nugget in `cm^3` and liters?

Answer 1

We need the density of gold, `rho_(Au)` `=` `19.32` `g*cm^-3`

Explanation:

So, we divide mass by density to get the volume:

`(93.3xx10^3*cancelg)/(19.32*cancelg*cm^-3)` `=` `4829.1` `cm^3`; approx a 5 litre volume.