The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and weighed 93.3 kg. What was the volume of this nugget in cm^3 and liters?

We need the density of gold, ${\rho}_{A u}$ $=$ $19.32$ $g \cdot c {m}^{-} 3$
$\frac{93.3 \times {10}^{3} \cdot \cancel{g}}{19.32 \cdot \cancel{g} \cdot c {m}^{-} 3}$ $=$ $4829.1$ $c {m}^{3}$; approx a 5 litre volume.