The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and a standard deviation of 0.8 in. What percentage of the snakes are longer than 16.6 in?
.02275 or 2.275%
If you have a graphing calculator, you can use it to find the answer!
Hit 2nd > VARS > 2: normalcdf(
This will prompt you for the lower bound, upper bound, mean (
First, fill in your lower and upper bounds. You want to find what percentage of snakes are longer than 16.6 inches, which means 16.6 and everything above that. Therefore,
lower bound = 16.6
upper bound = 999
Then press paste and enter, and you should get an answer of approximately .02275, or 2.275%.