The mass of water is 70.0 g. What is the energy required to heat a beaker of water at 18 degrees C to boiling?

1 Answer
Jul 27, 2016

Answer:

The energy required is 24 kJ.

Explanation:

The energy required to heat an object is given by the formula

#color(blue)(|bar(ul(color(white)(a/a) q = mcΔTcolor(white)(a/a)|)))" "#

where

#q# is the energy required
#m# is the mass
#c# is the specific heat capacity
#ΔT# is the change in temperature

In your problem,

#m = "70.0 g"#
#c = "4.179 J"·"°C"^"-1"·"g"^"-1"#
#ΔT = "(100 - 18) °C" = "82 °C"#

#q = 70.0 color(red)(cancel(color(black)("g"))) × "4.179 J"·color(red)(cancel(color(black)("°C"^"-1"·"g"^"-1"))) × 82 color(red)(cancel(color(black)("°C"))) = "24 000 J" = "24 kJ"#