Question

The mole fraction of NaCI in an aqueous solution is 0.132. How many moles of NaCI are present in 1 moles of this solution?

Answer 1

`0.132\ "moles"`

Explanation:

Mole fraction (`chi`) of `"NaCl"` in aqueous solution is `0.132`

So,

`chi_"NaCl" = "n"_"NaCl"/("n"_"NaCl" + "n"_"water")`

It’s given that

`"n"_"solution" = "n"_"NaCl" + "n"_"water" = "1 mol"`

So,

`chi_"NaCl" = "n"_"NaCl"/"1 mol"`

∴ `"n"_"NaCl" = chi_"NaCl" xx "1 mol = 0.132 mol"`