# The numbers #x,y z# satisfy #abs(x+2)+abs(y+3)+abs(z-5)=1# then prove that #abs(x+y+z)<=1#?

##### 1 Answer

Jul 25, 2018

Please see **Explanation.**

#### Explanation:

Recall that,

Jul 25, 2018

Please see **Explanation.**

Recall that,