# The perimeter of a rectangle is 162 ft. The lenght is 3 more than twice the width. How do you find the dimensions of the rectangle?

Sep 25, 2015

Width: $\text{26 ft}$
Length: $\text{55 ft}$

#### Explanation:

Let the length be $l$
Let the width be $w$

$l = 2 w + 3$

$2 \left(l + w\right) = 162$

$2 w + 3 + w = \frac{162}{2}$

$3 w + 3 = 81$

$3 w = 78$

$w = \text{26 ft}$

This means that

$l = 2 w + 3$

$l = 2 \left(26\right) + 3$

$l = \text{55 ft}$