# The perimeter of a rectangle is 48 in. If the length is twice the width, what is the length of the rectangle?

Aug 16, 2016

Length$= 16$ inches

#### Explanation:

Let $l$ be the length and $w$, width.

It is stated that, $l = 2 w \ldots \ldots \ldots \ldots \ldots . \left(1\right)$.

Now, the perimeter of the rectangle$= 48$.

$\Rightarrow 2 \left(l + w\right) = 48 , \mathmr{and} , l + w = 24$

$\Rightarrow 3 w = 24. \ldots \ldots \ldots \ldots . . \left[b y \left(1\right)\right]$

:. w=8, &, so, l=2w=16 inches.