# The perimeter of a square is 12 cm greater than that of another square. Its area exceeds the area of the other square by 39 sq cm. How do you find the perimeter of each square?

32cm and 20cm

#### Explanation:

let side of larger square be a and smaller square be b
4a - 4b = 12
so a - b = 3
${a}^{2} - {b}^{2} = 39$
(a+b)(a-b) = 39
dividing the 2 equations we get a+b = 13
now adding a+b and a-b, we get 2a = 16
a=8 and b=5
the perimeters are 4a=32cm and 4b = 20cm