# The population of town A increases from 1,346 to 1,500. In the same period, the population of town B increases from 1,546 to 1,800. What is the percent increase in population for town A and for town B? Which town had the greater percent of increase?

##### 1 Answer

Town A had a percentage increase of **11.4%** (1.d.p) and Town B had a percentage increase of **16.4%**.

Town B had the greatest percentage increase because 16.429495472 % > 11.441307578 %.

#### Explanation:

First, let's delve into what a percent actually is. A percentage is a specific amount **per** hundred (**cent**).

Next, I'll show you how to calculate the **percentage increase**. We have to first calculate the **difference** between the **new number** and the **original number**. The reason why we compare these is because we are finding **how much** a value has **changed**.

**Increase = New number - Original number**

To calculate the **percentage increase** we have to do the **increase** *divided* by the **original number**. This gives us the **increase**, but as a decimal, so we have to *multiply* the decimal by a **hundred** to give us a percentage.

**% Increase = (Increase ÷ Original number) × 100**

So let's get on to the question.

**Town A**

First, we have to find the *increase*.

Now let's *divide* the increase by the *original* number.

Finally the *percentage increase* is...

**Town B**

Again, we have to find the *increase*.

Let's *divide* by the *original number*.

Next, let's multiply it by a *hundred*.

**Which one had the greatest percentage increase?**

Town A = 11.441307578 %

Town B = 16.429495472 %

Town B had the greatest percentage increase because 16.429495472 % > 11.441307578 %.