The prime factorization of 540 is 2 x 2 x 3 x 3 x 3 x 5. How do you find the number of divisors of 540 other than 1?
1 Answer
Dec 6, 2017
Explanation:
Any positive divisor of
#2^a * 3^b * 5^c#
where:
#a in { 0, 1, 2 }#
#b in { 0, 1, 2, 3 }#
#c in { 0, 1}#
So there are
#3 * 4 * 2 = 24#
possible factors. One of those