# The prime factorization of 540 is 2 x 2 x 3 x 3 x 3 x 5. How do you find the number of divisors of 540 other than 1?

##### 1 Answer

Dec 6, 2017

#### Explanation:

Any positive divisor of

#2^a * 3^b * 5^c#

where:

#a in { 0, 1, 2 }#

#b in { 0, 1, 2, 3 }#

#c in { 0, 1}#

So there are

#3 * 4 * 2 = 24#

possible factors. One of those