# The product of three integers is 90. The second number is twice the first number. The third number two more than the first number. What are the three numbers?

##### 1 Answer
Oct 25, 2017

$22 , 44 , 24$

#### Explanation:

We assume the first number to be x.
First number = $x$

"twice the first number"
Second number = $2 \cdot \text{first number}$
Second number = $2 \cdot x$

"two more than the first number"
Second number = $\text{first number} + 2$
Third number = $x + 2$

The product of three integers is 90.
$\text{first number" + "second number" + "third number} = 90$
$\left(x\right) + \left(2 x\right) + \left(x + 2\right) = 90$

Now we solve for x
$4 x + 2 = 90$
$4 x = 88$
$x = 22$

Now that we know what x is, we can plug it in to find each individual number when $x = 22$
First = $x = 22$
Second = $2 x = 2 \cdot 22 = 44$
Third = $x + 2 = = 22 + 2 = 24$