The quantum numbers n = 4, l = 1, m_l = 0 could represent a valence electron in which atom in its ground state?

Answer choices are Fe, In, Pd, and Se, and answer key says it is Se.
I know that these quantum numbers refer to 4s electrons, so I eliminated B and C. How can I tell if the answer is Fe or Se, since both seem to have 4s electrons?
Thanks!

1 Answer
Nov 14, 2017

#l = 1# doesn’t represent s orbital. Given quantum numbers refers to either #4p^2# electron or #4p^5# electron.

Explanation:

#n = 4# represents that atom is in 4th period. So, answer is either Fe or Se

#l = 1# represents p orbital.
https://www.slideshare.net/mobile/FaysalKhan/lecture-7-presentation-716261

In p-block elements, the last (valence) electron enters in the outermost p-orbital. Therefore, atom belongs to p-block.

  • Fe is d-block element
  • Se is p-block element

Se is the correct answer.