Question

The ratio of the sum used of nth term of 2 Aps is `(7n+1):(4n+27),` Find the ratio of the `nth` `term..`?

Answer 1

The ratio of the sum used of nth term of 2 Aps is given as

`S_n/(S'_n)=(7n+1)/(4n+27)`

`=(n/2(2*4+(n-1)7))/(n/2(2*31/2+(n-1)4)`

So the ratio of nth term of 2 Aps will be given by

`t_n/(t'_n)=(4+(n-1)7)/(31/2+(n-1)4)=(14n-6)/(8n+23)`