The region under the curves #y=cosx-sinx, 0<=x<=pi/4# is rotated about the x axis. How do you sketch the region and find the volumes of the two solids of revolution?
1 Answer
Feb 22, 2018
volume = integration of[(pi*((cosx - sinx)^2)dx] from x = 0 to x = pi/4
volume = integration of[(pi*(1- sin2x)dx] from x = 0 to x = pi/4
volume = [(pi*(x + cos2x/2)] from x = 0 to x = pi/4
volume = [(pi(pi/4 + cospi/2)] -[(pi(0/4 + cos0/2)]
volume = [(pi(pi/4 +0)] -[(pi(0 + 1)]
volume =pi^2/4 -pi
