The rotational inertia I of a solid sphere is two fifths of the product of the sphere's mass M and it's radius squared r²?

I need help expressing the problem algebraically

1 Answer
Dec 29, 2017

#I = 2/5MR^2#

Explanation:

Let
R= radius
M = mass
#I# = rotational inertia

Radius squared means #R^2#

Product of #A and B = A*B = AB#, therefore
product of mass and its radius squared #= M *R^2 = MR^2#

Two fifth of # A and B= 2/5 ( A*B) = 2/5 AB#

Put them all together:

# I = 2/5 Mr^2 #