The solubility of cobalt II hydroxide, Co(OH)2, is 7.37e-6 M. What is the Ksp?

1 Answer
anor277
Apr 8, 2018

#K_"sp"=1.60xx10^-15#

Explanation:

We address the equilibrium....

#Co(OH)_2(s) rightleftharpoonsCo^(2+) + 2HO^-#

And here #K_"sp"=[Co^(2+)][HO^-]^2#...

Now we are given that the solubility of cobaltous hydroxide is #7.37xx10^-6*mol*L^-1#...and we can reformat the solubility product in these terms, given that #S=[Co^(2+)]#...and #[HO^-]=2S#...

And so #K_"sp"=Sxx(2S)^2=4S^3=4xx{7.37xx10^-6}^3=1.60xx10^-15#...

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