# The specific heat of water is 4.184 J/g times celsius degree. How much heat is required to raise the temperature of 5.0g of water by 3.0 C degrees?

Feb 25, 2018

62.76 Joules

#### Explanation:

By using the equation:
$Q = m c \Delta T$
$Q$ is the energy input in joules.
$m$ is the mass in grams/ kg.
$c$ is the specific heat capacity, which can be given Joules per kg or Joules per gram per kelvin/Celcius. One must be observant if it is given in joules per kg per kelvin/Celcius, kilojoules per kg per kelvin/Celcius etc. Anyhow, In this case we take it as joule per gram.
$\Delta T$ is the temperature change (in Kelvin or Celcius)
Hence:
$Q = m c \Delta T$
$Q = \left(5 \times 4.184 \times 3\right)$
$Q = 62.76 J$