Question

The sum of 3 consecutive integral numbers is 117. What are the numbers?

Answer 1

`38,39,40`

Explanation:

If the second of the three numbers is `n`, then the first and third are `n-1` and `n+1`, so we find:

`117 = (n-1)+n+(n+1) = 3n`

Dividing both ends by `3` we find:

`n = 117/3=39`

So the three numbers are:

`38, 39, 40`