# The sum of 3 consecutive integral numbers is 117. What are the numbers?

May 24, 2016

$38 , 39 , 40$

#### Explanation:

If the second of the three numbers is $n$, then the first and third are $n - 1$ and $n + 1$, so we find:

$117 = \left(n - 1\right) + n + \left(n + 1\right) = 3 n$

Dividing both ends by $3$ we find:

$n = \frac{117}{3} = 39$

So the three numbers are:

$38 , 39 , 40$