The sum of 6 consecutive integers is 393. What is the third number in this sequence?

2 Answers
May 12, 2018

65

Explanation:

Let the first number be #n#

Then the 6 consecutive numbers are:

#n+(n+1)+(n+2)+(n+3)+(n+4)+(n+5) = 393#

#6n+15=393#

#n=(393-15)/6#

#n=63" so "n+2= 3^("rd")" number" = 65#

May 12, 2018

65

Explanation:

Let the numbers be

#n-2, n-1, n, n+1, n+2, n+3#

These add to 393 so

#n-2+ n-1+ n+ n+1+ n+2+ n+3= 393#

#6n+3=393#

#6n=390#

#n=65#