The sum of the squares of two natural numbers is 58. The difference of their squares is 40. What are the two natural numbers?
1 Answer
Apr 26, 2017
The numbers are
Explanation:
We let the numbers be
#{(x^2 + y^2 = 58), (x^2 - y^2 = 40):}#
We can solve this easily using elimination, noticing that the first
#2x^2 = 98#
#x^2 = 49#
#x = +-7#
However, since it is stated that the numbers are natural, that's to say greater than
Now, solving for
#7^2 + y^2 = 58#
#y^2 = 9#
#y = 3#
Hopefully this helps!