The sum of three consecutive integers is 141. what is the smallest integer ?

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Answer 1 · 2018-05-16T12:38:14

#46#

Let the smallest integer be #x#. Then the next two integers are #x+1# and #x+2#.

So, we have:

#x+(x+1)+(x+2)=141#

#x+x+1+x+2=141#

#3x+3=141#

#3x=138#

#x=138/3=46#

Therefore, the smallest integer is #46#.