# The tension in a 2 m length of string that whirls a 1 kg mass at 4 m/s in a horizontal circle is calculated to be 8 N. How do you alculate the tension for the following case: twice the mass?

Nov 12, 2015

$16 \text{N}$

#### Explanation:

The tension in the string is balanced by the centripetal force.

This is given by $F = \frac{m {v}^{2}}{r}$

This is equal to $8 \text{N}$.

So you can see that, without doing any calculations, doubling $m$ must double the force and hence the tension to $16 \text{N}$.