# The terminal side of #theta# lies on the line #2x-y=0# in quadrant III, how do you find the values of the six trigonometric functions by finding a point on the line?

##### 2 Answers

#### Answer:

#### Explanation:

Any relation of the form

So

Furthermore, we can see that

so we have the situation in the image below for a point on the line in Q III:

The six trigonometric values can be determined by applying their definitions based on "adjacent", "opposite", and "hypotenuse" sides.

#### Answer:

The answer is:

Because

#### Explanation:

Using the distance formula you arrive at the square root of 5. This answer is verified via a Larson Precalculus book in the answer section.

EDIT: How I did this was by picking a relivant point that I could work with. You could also use the unit circle equation of