Question

The total length of a wall is 456 cm. The wall has 3 bookcases. A is 132 cm, B is 94 cm, and C is 108 cm. The carpenter plans on building 2 more bookcases (D & E) along that same wall. The two bookcases will have equal widths? Part 1 of 2

Answer 1

The equation is `334+2x=456`. Width of `D` and `E` bookcases is `61` `cm.` each.

Explanation:

As bookcases `D` and `E` have equal width, let this width be `x` `cm.`

Now as width of `A` is`132` cm., that of `B` is `94` cm., of `C` is `108` cm. and that of `D` and `E` is `x` cm.

total width of all bookcases is `132+94+108+x+x` and this wll be width of wall `456` cm., hence

`132+94+108+x+x=456`

or `334+2x=456`, which is the equation.

Thiis means `334-334+2x=456-334`

or `2x=122`

i.e. `2x xx 1/2=122xx 1/2`

or `x=122/2=(cancel122^61)/(cancel2^1)=61`

Width of `D` and `E` bookcases is `61` `cm.` each.