The total pressure of a mixture of helium and argon in a closed cylinder is 3.0 atm. If the partial pressure of the argon is 0.365 atm, what is the partial pressure exerted by the helium?

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Answer 1 · 2018-05-24T00:24:05

#2.635 \ "atm"#

Dalton's law of partial pressures states that:

#P_"total"=P_1+P_2+P_3+...+P_n#

where #P_1,P_2,P_3,...,P_n# are the partial pressures of gas #1,2,3,...,n#.

Here, there are only two gases, and so:

#P_"total"=P_(Ar)+P_(He)#

And so, plugging in the given values, we get:

#3 \ "atm"=0.365 \ "atm"+P_(He)#

#P_(He)=2.635 \ "atm"#