Question

The velocity of an object with a mass of `3 kg` is given by `v(t)= - 5sin 2 t + cos 7 t`. What is the impulse applied to the object at `t= pi /6`?

Answer 1

`int F*d t=-10,098 "N.s"`

Explanation:

`v(t)=-5sin2t+cos7t`
`d v=(-10cos2t-7sin7t)d t`
`int F*d t=int m*d v`
`int F* d t=m int(-10cos2t-7sin7t)d t`
`int F* d t=m(-5sint+cos7t )`
`int F*d t=3((-5sin pi)/6+cos(7pi)/6)`
`int F*d t=3(-5*0,5-0,866)`
`int F*d t=3(-2,5-0,866)`
`int F*d t=-10,098 "N.s"`