The velocity of an object with a mass of #4 kg# is given by #v(t)= sin 3 t + cos 6 t #. What is the impulse applied to the object at #t= pi /3 #?
1 Answer
Mar 7, 2018
The impulse is
Explanation:
We know that impulse is change in momentum. Momentum is given by
So we want to find the rate of change, or the derivative of the velocity function, and evaluate it at time
#v'(t) = 3cos(3t) - 6sin(6t)#
#v'(pi/3) = 3cos(3(pi/3)) - 6sin(6(pi/3))#
#v'(pi/3) = -3#
Then we have
#J = mDelta v#
#J= 4(-3)#
#J = -12 kg" "Ns#
Hopefully this helps!